Question:
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input:(2 -> 4 -> 3) + (5 -> 6 -> 4)
Output:7 -> 0 -> 8
Anwser 1:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {
// Start typing your C/C++ solution below
if(l1 == NULL && l2 == NULL) {
return NULL;
}
ListNode *retList = new ListNode(0);
ListNode *tmpList = retList;
ListNode *head1 = l1;
ListNode *head2 = l2;
int carry = 0;
while(head1 != NULL && head2 != NULL){
int sum = carry + head1->val + head2->val;
carry = sum / 10;
tmpList->next = new ListNode(sum % 10);
tmpList = tmpList->next;
head1 = head1->next;
head2 = head2->next;
}
while(head1 != NULL){
int sum = carry + head1->val;
carry = sum / 10;
tmpList->next = new ListNode(sum % 10);
tmpList = tmpList->next;
head1 = head1->next;
}
while(head2 != NULL){
int sum = carry + head2->val;
carry = sum / 10;
tmpList->next = new ListNode(sum % 10);
tmpList = tmpList->next;
head2 = head2->next;
}
if(carry == 1){
tmpList->next = new ListNode(1);
}
tmpList = retList;
retList = retList->next;
delete tmpList;
return retList;
}
};
Anwser 2:
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